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In a Young's experiment, let light of lambda = 5.48 xx 10^(-7) m and 6.85 xx 10^(-8) m be used in turn keeping D and d constant. Compare the fringe widths in the two cases : |
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Answer» SOLUTION :Fringe Width `beta = (D lambda)/(d)` `therefore (beta_(1))/(beta_(2)) = (lambda_())/(lambda_(2)) = (5.48 xx 10^(-7))/(6.85 xx 10^(-8))` or `(beta_(1))/(beta_(2) = 8/1` i.e.`beta_(1) : beta_(2) = 8 : 1` |
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