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In a Young' sdouble slit experiment the slit separation is 0.5 m and distance of screen is 5m. For a monochromatic light of wavelength 500nm, the distance of 3^(rd) maxima from 2^(nd) minima on the other side is : |
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Answer» `2.5 mm` `y_(N2)(min) = (n_(2) - 1)/(2)(lambda D)/(d), n_(2) = 2` `therefore y_(n1) + y_(n2) = (n_(1) + n_(2) - 1/2)(lambdaD)/(d)` ` = ( 3 + 2 - 1/2)(lambda D)/(d)` ` = (9)/(2) xx (lambdaD)/(d)` `(9)/(2) xx (500 xx 10^(-6) xx 5)/(0.5)` ` = 22.5 xx 10^(-3)m`. |
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