1.

In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.

Answer»

SOLUTION :`LAMBDA=(1.2xx10^(-2)xx0.28xx10^(-3))/(4xx1.4)m=600nm`


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