1.

In a zero order reaction, for every 10^(@) rise of temperaure, reaction rate is doubled. If the temperature 10^(@)C to 100^(@)C, the reaction rate will become:

Answer»

256 times
512 times
64 times
128 times

Solution :b) For every `10^(@)` rise in TEMPERATURE, REACTION rate increase by 2.
`(r_(100^(@))C)/(r_(10^(@))C) = 2^((100-10))/(10) = 2^(9)=512` times.


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