1.

In a zero order reactionn 47.5% of the reactant remains at the end of 2.5 hours. The amount of reactant consumed in one hour is

Answer»

0.105
0.32
0.526
0.21

Solution :`C_(0)-C_(t)=K.t`……………(1), `x=Kxx1`….2 `52.5/x=2.5/1impliesx=52.5/2.5=21`


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