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In ∆ABC, ∠B = 90o. D and E divide the sides CB and AB in the ratio 1 : 2. Prove that 9(AD2+ BE2) = 13 AC2. |
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Answer» Step-by-step explanation: In ∆ACB , iii ) By adding ( 1 ) and ( 2 ) , we get 9( AQ² + BP² ) = 13AC² + 13BC²----( 3 ) But in ∆ACB , AB² = AC² + BC² ---( 4 ) [ By Phythogarian theorem ] substitute ( 4 ) in ( 3 ) , we get 9( AQ² + BP² ) = 13AB² Hence proved. Ok |
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