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In ∆ ABC, if a = 18, b = 24, c = 30 and ∠C = 90°, find sin A and sin B. |
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Answer» \(\frac{sin\,A}{a}=\frac{sin\,B}{b}=\frac{sin\,C}{c}\) \(\frac{sin\,A}{18}=\frac{sin\,B}{24}=\frac{sin\,90°}{30}\) \(\frac{sin\,A}{18}=\frac{sin\,B}{24}=\frac{1}{30}\) \(sin\,A=\frac{18}{30}=\frac{3}{5}\) \(sin\,B=\frac{24}{30}=\frac{4}{5}\) |
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