1.

In above equation No. 304, the potential energy of the satellite is

Answer»

`-(GmM)/((R+h)^(2))`
`-(GmM)/(2(R+h)^(2))`
`-(GmM)/((R+h))`
`-(GmM)/(2(R+h))`

SOLUTION :`"POTENTIAL ENERGY "=-(GmM)/(r)=-(GmM)/((R+h))`.


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