1.

In above question, the radius of gyration of the system about axis AB is :

Answer»

`SQRT(5)a`
`sqrt(2a)`
`sqrt(3)a`
`2a`

Solution :`I_(AB)=Mk^(2)=10mk^(2)`
`therefore 10mk^(2)=50MA^(2)`
`k=sqrt((50)/(10)).a=sqrt(5A)`


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