In ACB, C = 90°, AC-3, BC=4. Find the ratio of sinA,cosA,tanB,solve b

1.	In ACB, C = 90°, AC-3, BC=4. Find the ratio of sinA,cosA,tanB,solve by Pythagoras theorem
Answer» Step-by-step EXPLANATION: ΔACB is right angled TRIANGLE. angle C=90° by PYTHAGORAS therom, (AB)²=(AC) ²+(BC) ² (AB)² =(3)²+(4)² (AB)² =9+16 (AB)² =25 AB =5 sinA=AB/AC =5/3 cosA=BC/AC =4/3 tanB=AB/BC =5/4 HOPE IT IS HELPFUL FOR YOU PLZ THANKS MY ANSWER AND MARK ME AS BRILLIANT....

In ACB, C = 90°, AC-3, BC=4. Find the ratio of sinA,cosA,tanB,solve by Pythagoras theorem

Answer»

Step-by-step EXPLANATION:

ΔACB is right angled TRIANGLE.

angle C=90°

by PYTHAGORAS therom,

(AB)²=(AC) ²+(BC) ²

(AB)² =(3)²+(4)²

(AB)² =9+16

(AB)² =25

AB =5

sinA=AB/AC

=5/3

cosA=BC/AC

=4/3

tanB=AB/BC

=5/4

HOPE IT IS HELPFUL FOR YOU PLZ THANKS MY ANSWER AND MARK ME AS BRILLIANT....