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In acidic medium, the rate of reaction between `BrO_(3)^(ɵ)` and `Br^(ɵ)` is given by the expression `(-d[BrO_(3)^(ɵ)])/(dt) =k[BrO_(3)^(ɵ)][Br^(ɵ)][H^(o+)]^(2)`A. The rate constant of overall reaction is `4s^(-1)`.B. The rate of reaction is independent of the concentration of acid.C. The change in `pH` of the solution will no affect the rate.D. Doubling the concentration of `H^(o+)` ions will increase the reaction rate by `4` times. |
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Answer» Correct Answer - D Order w.r.t. `[H^(o+)] = 2`. Hence, doubling the concentration of `[H^(o+)]` ions will increase the reaction rate by `4` times.Correct Answer - D Order w.r.t. `[H^(o+)] = 2`. Hence, doubling the concentration of `[H^(o+)]` ions will increase the reaction rate by `4` times. |
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