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In amixure of NaOH and NaCl 50% sodium is present. Calculate mass % of NaOH in the solution. |
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Answer» `95.2%` `n_(NAOH)=a, n_(NaCl)=b` 40a+58.5b=100 . . . .(i) `axx23+bxx23=50gm` `a+b=(50)/(23)` . . . .(ii) `40a+40b=(50xx40)/(23)` 40a+58.5b=100 `18.5b=100-(200)/(23)` `b=(100-86.9)/(18.5)=0.7`. `a=(50)/(23)-0.7=2.17-0.7` In 100 gm mixture `rArr W_(NaOH)=58.8rArr58.8%` APPROX. |
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