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In an a.c. circuit an alternating voltage V = 200 sqrt(2) sin 100t volts is connected to a capacitor of capacitance 1 uF. The rms value of the current in the circuit is

Answer»

20 mA
10 mA
100 mA
200 mA

Solution :Here, `V = 200sqrt(2) sin 100 t`, HENCE `V_(m) = 200 sqrt(2) V` or `V_(rms) = (200 sqrt(2))/sqrt(2) = 200 V` and `omega = 100 s^(-1)`. As `C=1 MUF= 10^(-6)` F, Hence, `X_(C) =1/(Comega) =1/(10^(-6) xx 100) = 10^(4) Omega`
`therefore` Value of rms current `I_(rms) = V_(rms)/X_( C) =200/10^(4) = 2 xx 10^(-2) A = 20 mA`


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