In an a.c. circuit, instantaneous voltage and current are V = 200 sin 300 t "volt" and i = 8 cos 300t ampere respectively. What is the average power dissipated in the circuit?

In an a.c. circuit, instantaneous voltage and current are V = 200 sin

1.	In an a.c. circuit, instantaneous voltage and current are V = 200 sin 300 t "volt" and i = 8 cos 300t ampere respectively. What is the average power dissipated in the circuit?
Answer» Solution :As the PHASE DIFFERENCE between current and voltage is `pi/2`. `THEREFORE P_("av") = I_("VEV") COS. (pi)/(2) =0`

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In an a.c. circuit, instantaneous voltage and current are V = 200 sin 300 t "volt" and i = 8 cos 300t ampere respectively. What is the average power dissipated in the circuit?

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