1.

In an A.C. circuit of frequency 400/pi Hz is of capacitance CmuF and reactance of capacitance is 25Omega then the value of C = .....

Answer»

`25muF`
`50muF`
`400muF`
`100muF`

Solution :`f=400/pi` HZ, `X_C=25Omega`
`omega=2pif =2pixx400/pi`=800 rad/s
`X_C=1/(omegaC)`
`THEREFORE C=1/(omegaX_C)=1/(800xx25)`
`therefore C=1/20000=50xx10^(-6) F = 50 muF`


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