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In an A.C. circuit of frequency 400/pi Hz is of capacitance CmuF and reactance of capacitance is 25Omega then the value of C = ..... |
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Answer» `25muF` `omega=2pif =2pixx400/pi`=800 rad/s `X_C=1/(omegaC)` `THEREFORE C=1/(omegaX_C)=1/(800xx25)` `therefore C=1/20000=50xx10^(-6) F = 50 muF` |
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