1.

In an a.c. circuit, the applied voltage is E=E_0sinomegatand the resulting current in the circuit is I=I_0sin(omegat-pi/2). The power consumed in the circuit is given by :

Answer»

`P=E_0I_0/2`
`P=E_0I_0/sqrt2`
P=0
`P=sqrt2E_0I_0`

ANSWER :C


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