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In an A.C. circuit, the current flowing is I = 5 sin (100t-pi//2) ampere and the potential difference is V = 200 sin (100t) volts. The power consumption is equal to |
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Answer» Solution :CURRENT (I) `= 5 sin (100t-pi//2)` and voltage (V) `= 200 sin(100 t)`. Comparing the given equation, with the standard equation, we find that phase angle between current and voltage is `phi=pi//2 = 90^(@)`. Powe consumption `P=I_(rms)V_(rms)cos phi` `= I_(rms)V_(rms) cos 90^(@)=0` |
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