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In an a.c. Circuit the voltage applied is `E=E_(0) sin (omega)t`. The resulting current in the circuit is `I=I_(0)sin((omega)t-(pi/2))`. The power consumption in the circuit is given byA. `P=(E_(0)I_(0))/(sqrt(2))`B. `P=sqrt(2) E_(0) I_(0)`C. `P=(E_(0)I_(0))/2`D. `P=0` |
Answer» Correct Answer - D Phase angle `varphi=90^(@)`, so power `P=Vi cos varphi=0` |
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