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In an A.C. circuit, voltage applied is V = 220 sin 100t. If the impedance is 110Omega and phase difference between current and voltage is 60^@, the power consumption is equal to ........ |
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Answer» Solution :Comparing EQUATION V=220 sin 100t with `V=V_m sin omegat`, `V_m`=220 `|Z|=110 Omega` `therefore I_m=V_m/"|Z|"=220/110`=2A `delta=60^@ =pi/3` rad `P=(V_mI_m)/2 COS delta =(220xx2)/2 cos 60^@` `=(220xx2)/2 xx1/2`=110 W |
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