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In an △ABC, AB=AC and ∠C = 80°. Find each of the equal angles. |
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Answer» ∆ABC=180°=> ANGLE A = angle B = angle C=> A+B+C=180°=> A+B+80°=180°=> A+B=180°-80°=> A+B=100°let angle A and angle B be x and xso,=>x+x=100°=>2x=100°=>x=100°/2=50°Therefore,the three ANGLES MEASURE 50°,50° and 80° |
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