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| 1. |
In an `AC` circuit, the mass value of the current `I_("rms")` is related to the peak current `I_(0)` asA. `I_("rms") = (1)/(pi) I_(0)`B. `I_("rms") = (1)/(sqrt(2)) I_(0)`C. `I_("rms") = sqrt(2) I_(0)`D. `I_("rms") = pi I_(0)` |
| Answer» Correct Answer - 2 | |