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In an `AC` circuit, `V` and `I` are given by `V=100sin(100t)volts, I=100sin(100t+(pi)/3)mA`. The power dissipated in circuit isA. `10^(4)W`B. `10W`C. `2.5W`D. `5W` |
Answer» Correct Answer - C `V_(0) = 100 V i_(0) = 100 mA = 100 xx 10^(-3) = 0.1 A phi = 60^(@)` `P = (1)/(2) V_(0)i_(0) cos phi = (1)/(2) xx 100 xx 0.1 xx (1)/(2) = 2.5 W` . |
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