In an AC, series L-C-R circuit, `R=X_(L)=X_(C)` and applied AC, voltage is V. Then match the following two columns.

In an AC, series L-C-R circuit, `R=X_(L)=X_(C)` and applied AC, voltag

1.	In an AC, series L-C-R circuit, `R=X_(L)=X_(C)` and applied AC, voltage is V. Then match the following two columns.
Answer» Correct Answer - (A-q); (B-q); (C-r); (D-p) Z=R [As `X_(L)=X_(C))]` `therefore I=V/Z=V/R` Now, `V_(R) = IR=V` `V_(C) = IX_(C)=V=V_(L)` `V_(RL) = sqrt(V^(2)+V^(2)) = sqrt(2)V` `V_(LC) = V-V=0`

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In an AC, series L-C-R circuit, `R=X_(L)=X_(C)` and applied AC, voltage is V. Then match the following two columns.

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