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In an adiabatic process, `R = (2)/(3) C_(v)`. The pressure of the gas will be proportional to:A. `T^(5//3)`B. `T^(5//2)`C. `T^(5//4)`D. `T^(5//6)` |
Answer» Correct Answer - B `R = (2)/(3) C_(v)` We know, `C_(P) - C_(V ) = R` or `gamma - 1 = (R )/(C_(V))` or `R = C_(V) (gamma - 1)` Comparing `gamma = 5//3` `P^(1 - gamma) T^(gamma) =` constant = `K` or `P prop T^((gamma//gamma -))` Given `gamma = 5//3` `gamma//(gamma - 1) = 5//2` so, `P prop T^(5//2)` |
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