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In an adsorption expetiment, a graph between log (x/m) varuse log P was found to be linear with a slope of 45^(@). The intercept on the log (x/m) axis was found to be 0.3010. Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 0.5 atmosphere. |
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Answer» Solution :According to Freundlich equation, `x/m =k P^(1//) or log ""(x)/(m)=log k+1/n log P` `THEREFORE` Plot of `x/m` varsus log P is linear with SLOPE `=1/n` and INTERCEPT `=log k.` Thus, `1/n = TNA theta = TAN 45^(@)=1 or n=1` `log k =0.3010 or k= "Antilig" 0.3010=2` At `P =0.5 atm, x/m =k P^(1//n)=2xx(0.5)^(1)=1.0` |
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