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In an AP:1 given a =5, d = 3, a = 50, find n and S22 what​

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Answer:

N=16 and S(22)=374

a(n)=50

a=5

d=3

a(n)=a+(n-1)d

50=5+(n-1)3

45=(n-1)3

n-1=45/3=15

n=15+1=16

S(n)=n/2[2a+(n-1)d]

S(22)=11[10+(21)3]=11[10+24]=11(34)=374

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