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In an Arithmetic progressionFind n |
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Answer» -step EXPLANATION:a=3 d=4Sn= 903hence 903= n/2( a+ an)903×2= n[ 3+ 3+(n-1)d ]903×2= n(6+ 4N- 4)1806= 2n+ 4n^24n^2 + 2n -1806 = 02n^2 + n - 903= 0 by solving the above quadratic equation we get (for solution please check the attachment)n=21hope this HELPS you... |
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