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In an arthematic sequence s4=126,a1=9. find the fourth term of the sequence |
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Answer» t4=54Step-by-step EXPLANATION:s4=126a1=9s4=4/2(2a1+3d)126=2(2a1+3d)2a1+3d=126/2=634th TERM t4=a1+3d=(2a1+3d)-a1t4=63-a1=63-9=54 |
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