1.

In an atom, an electron is moving with a speed of 6200 m/s which the position of an electron can be locates is (h=6.6xx10^(-34)kgm^(2)s^(-1), mass of electron e_(m)=9.1xx10^(-31)kg)

Answer»

`1.52xx10^(-4)m`
`5.10xx10^(-3)m`
`1.92xx10^(-3)m`
`3.84xx10^(-3)m`

SOLUTION :`Deltav=0005/100xx600=0.03`
`Delta X xx mDeltav=h/(4pi)`
`Deltax=h/(4pi mDeltav)=(6.6xx10^(-34))/(4xx3.14xx9.1xx10^(-31)xx6.03)`
`=1.92xx10^(-3)m`


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