In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(150t+(pi)/(3))A`. The power dissipated in the circuit isA. 106 WB. 150 WC. 5625 WD. zero

In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(

1.	In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(150t+(pi)/(3))A`. The power dissipated in the circuit isA. 106 WB. 150 WC. 5625 WD. zero
Answer» Correct Answer - C Compare C = 150 sin (150 t) with `V = V_(0)sin omega t`, we get, `V_(0)=150 V` Compare `I = 150 sin (150 t+(pi)/(3))` with `I = I_(0)sin(omega t+ phi)`, we get `I_(0)=150A, phi = (pi)/(3)=60^(@)` The power dissipated in ac circuit is `P=(1)/(2)V_(0)I_(0)cos phi=(1)/(2)xx150xx150xx cos 60^(@)` `=(1)/(2)xx150xx150xx(1)/(2)=5625 W`

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In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(150t+(pi)/(3))A`. The power dissipated in the circuit isA. 106 WB. 150 WC. 5625 WD. zero

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