1.

In an electron microscope, if the potential is increased from 20 kV to 80 kV, the resolving power R of the microscope will become :

Answer»

R
2R
4R
`(R)/(2)`

Solution :RESOLVING POWER `R prop V^(1//2)`
here `V_(1)=20 KV`
`V_(2)=20 KV`
`:.(V_(2))/(V_(1))=4`
`:.` So resolving power becomes 2R.


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