1.

In an estimation of sulphur by Carius method, 0.160g of the substance gave 0.466g of barium sulphate. The percentage of sulphur in the compound is[At mass of Ba=137, S=32, O=16] :

Answer»

`25.0%`
`4.0%`
`54.0%`
`40.0%`

SOLUTION :`underset(233)(BaSO_(4))-=underset(32)(S)`
`233g` of `BaSO_(4)` CONTAIN SULPHUR `=32G`
`0.466g` of `BaSO_(4)` contain sulphur
`=(32)/(233)xx0.466=0.064`
`%` Sulphur `=(0.064)/(0.160)xx100=40%`


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