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In an experiment, 17g of ice is used to bring down the temperature of 40 g of water at 34℃ to its freezing temperature. The specific heat capacity of water is 4.2 J kg-1 K-1. Calculate the specific latent heat of ice. State one important assumption made in the above calculation. |
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Answer» Mass of ice m1 = 17 g Mass of water m2 = 40 g. Change in temperature = 34 – 0 = 34K Specific heat capacity of water is 4.2Jg-1K-1. Assuming there is no loss of heat, heat energy gained by ice (latent heat of ice), Q= heat energy released by water Q = 40 × 34 × 4.2 = 5712 J. Specific latent heat of ice = L = Q/m = 5712/17 = 336Jg-1 |
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