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In an experiment for determination of refractive index of glass of prism by i - delta plot, it was found that a ray incident at angle 35^(@) , suffers a deviation of 40^(@) and that it emerges at angle 79^(@). In that case which of the following is closest to the maximum possible value of the refractive index? |
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Answer» 1.5 `or, " " 40^(@) = 35^(@) + 79^(@) - A or, A = 74^(@)` Now, the minimum value of angle of deviation, `delta_(m) le 40^(@)` `"In that case", mu le (sin""(A + delta_(m))/(2))/(sin""(A)/(2))` `or, " " mu le(sin""(74^(@) + 40^(@))/(2))/(sin""(74^(@))/(2))` `or, " " mu le 1.39` `therefore " " mu_(max) = 1.5` 
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