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In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow `P = (a^(3)b^(2))/(cd) %` error in `P` isA. `14%`B. `10%`C. `7%`D. `4%` |
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Answer» Correct Answer - A `P=(a^(3)b^(2))/(cd)` Error in `((DeltaP)/(P))=3((Deltaa)/(a))+2((Deltab)/(b))+((Deltac)/(c))+((Deltad)/(d))` `=3(1%)+2(2%)+3%+4%=14%` |
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