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In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12xx10^(-15)V s. Calculate the value of Planck's constant. |
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Answer» SOLUTION :Slope `=4.12xx10^(-15)Vs` `(h)/( e)=4.12xx10^(-15)` `h=4.12xx10^(-15)xx1.6xx10^(-19)=6.6xx10^(-34)JS` |
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