In an experiment with a post office box, the radio of arms are `1000 : 10`. If the value of the third resistance is `999 Omega`, find the unknows resistance.

In an experiment with a post office box, the radio of arms are `1000 :

1.	In an experiment with a post office box, the radio of arms are `1000 : 10`. If the value of the third resistance is `999 Omega`, find the unknows resistance.
Answer» Correct Answer - `9.99 Omega` In the given case, the ratio of arms is `1000: 10`. `(P)/(Q) = (1000)/(10) = 100` Third resistance is `R = 999 V`. Lat `X` be the unknows resistance. Then, `(P)/(Q) = (R )/(X)` or `X = (Q)/(P) xx R = (1)/(100) xx999= 9.99 Omega`

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In an experiment with a post office box, the radio of arms are `1000 : 10`. If the value of the third resistance is `999 Omega`, find the unknows resistance.

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