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In an experiment with Foucault's apparatus, the various distances used are as follows : Distance between the rotating and the fixed mirror = 16 m Distance between the lens and the rotating mirror = 6 m, Distance between the source and the lens = 2 m. When the mirror is rotated at a speed of 356 revolutions per second, the image shifts by 0.7 mm. Calculate the speed of light from these data. |
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Answer» R= distance between fixed and rotating mirror =16 m w=Angular speed = 356 rev/s `=356xx2pi rad/sec` b=distance between lens and rotating mirror 6M a=Distance between source and lens =2M s=shift in image `=0.7m=0.7xx10^3m` So speed of light is given by `c4R^2(WA)/(s(R+b))` `=(4x(16)^2xx356xx2pixx2)/((0.7)xx10^-3(16+6))` `=2.975xx10^8m/s` |
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