In an ideal gas without preferred direction of motion of molecules,A. `V_(x)=V_(y)=V_(z)`B. `V_(x)^(2)=V_(y)^(2)=V_(z)^(2)`C. `barV_(x)^(2)=barV_(y)^(2)=barV_(z)^(2)`D. None of the above

In an ideal gas without preferred direction of motion of molecules,A.

1.	In an ideal gas without preferred direction of motion of molecules,A. `V_(x)=V_(y)=V_(z)`B. `V_(x)^(2)=V_(y)^(2)=V_(z)^(2)`C. `barV_(x)^(2)=barV_(y)^(2)=barV_(z)^(2)`D. None of the above
Answer» Correct Answer - C An isotropic gas is one which have same properties throughout and their molecules are all moving random directions, so only average values of square of their velocity components are equal.

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In an ideal gas without preferred direction of motion of molecules,A. `V_(x)=V_(y)=V_(z)`B. `V_(x)^(2)=V_(y)^(2)=V_(z)^(2)`C. `barV_(x)^(2)=barV_(y)^(2)=barV_(z)^(2)`D. None of the above

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