Saved Bookmarks
| 1. |
In an ideal transformer, the voltage is stepped down from 11 kV to 220 V. If the primary current be 100 A, the current in the secondary should be …… |
|
Answer» 5 KA For an ideal transformer `P_1=P_2` `epsilon_1I_1=epsilon_2I_2` `I_2=epsilon_1/epsilon_2I_1` `=(11xx10^3xx100)/220` `=5xx10^3` A `therefore I_2`= 5 kA |
|