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In an inductor of self-inductance L=2 mH, current changes with time according to relation `i=t^(2)e^(-t)`. At what time emf is zero ?A. 2sB. 1sC. 4sD. 3s |
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Answer» Correct Answer - A `I=t^2e^(-t)` `e=L"dl"/"dt"` here emf is zero when `"dl"/"dt"=0` `"dl"/"dt"=2te^(-tau)-t^2 e^(-tau)=0` `rArr te^(-tau) (t-2) = 0 rArr t =2` sec |
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