In an interference pattern the path difference between waves starting from S_(1) and S_(2) and reaching at P is 1.5 microns i.e. S_(2)P - S_(1)P = 1.5 microns. If the wavelength of light used be 6000 Å, then the point P is :

In an interference pattern the path difference between waves starting

1.	In an interference pattern the path difference between waves starting from S_(1) and S_(2) and reaching at P is 1.5 microns i.e. S_(2)P - S_(1)P = 1.5 microns. If the wavelength of light used be 6000 Å, then the point P is :
Answer» II ND Max. II nd Min. Third min. Fourth min. Solution :PATH difference = `S_(2)P - S_(1)P = 1.5 xx 10^(-6)` m `= (1.5 xx 10^(-6))/(6 xx 10^(-7)) lambda` ....(i) In terms of `lambda`, `= 2.5 lambda = (2N -1) lambda/2`...(ii) `therefore n = 3`.

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In an interference pattern the path difference between waves starting from S_(1) and S_(2) and reaching at P is 1.5 microns i.e. S_(2)P - S_(1)P = 1.5 microns. If the wavelength of light used be 6000 Å, then the point P is :

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