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In an interference pattern, the ratio of maximum intensity to minimum intensity is 25:1. Find the ratio of the amplitudes and intensities of the two interfering waves. |
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Answer» SOLUTION :We have `(I_("max"))/(I_("MIN"))=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=25/1=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))` `:.(a_(1)+a_(2))/(a_(1)-a_(2))=5/1` `5a_(1)-5a_(2)=a_(1)+a_(2)""4a_(1)=6a_(2)""(a_(1))/(a_(2))=6/4=3/2` As `I_(1)PROP a_(1)^(2)` and `I_(2) prop a_(2)^(2)` `(I_(1))/(I_(2))=(a_(1)^(2))/(a_(2)^(2))=(3/2)^(2)=9/4""I_(1):I_(2)=9:4` |
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