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In an interference the intensity of two interfering waves are I and 4I respectively. They produce intensity at two point A and B with phase angle of (pi)/(2) and pi it respectively. Then differation in between them is ...... |
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Answer» I Here `I_(1)=I` and `I_(2) =4I, phi_(1)=(pi)/(2), phi_(2)= pi` On point `A I_(A)=I+4I+2 sqrt(4I^(2)) "cos" (pi)/(2)` On point `B I_(B)=I+4I+2 sqrt(4I^(2)) "cos" pi` `=5I-4I` =I Now `I_(A)-I_(B)=5I-I=4I` |
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