In an interfernce expriment , third bright fringe is obtained on the screenwith a light of 700 nm. Whatshould be thewavelength of the light source in order to obtain fifthbrightfringeat the same point ?

In an interfernce expriment , third bright fringe is obtained on the s

1.	In an interfernce expriment , third bright fringe is obtained on the screenwith a light of 700 nm. Whatshould be thewavelength of the light source in order to obtain fifthbrightfringeat the same point ?
Answer» 420 m 500 m 750 m 630 m Solution :From ` X = (n lambda D)/d = (n. lambda.D )/d` ` lambda. = ( n lambda)/(n.) = (3 xx 700 nm)/5 = 420 nm `

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In an interfernce expriment , third bright fringe is obtained on the screenwith a light of 700 nm. Whatshould be thewavelength of the light source in order to obtain fifthbrightfringeat the same point ?

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