1.

In an isosceles triangle ABC, AB = AC and 2 A=30. . Find < B and C.​

Answer»

Given AB=AC∠A=(2x+40) ∘ ∠B=(4x+30) ∘ we have ∠B=∠C(∵AB=AC)and sum of all the ANGLES of a triangle=180 ∘ ∴∠A+∠B+∠C=180 ∘ (2x+40) ∘ +(4x+30) ∘ +(4x+30) ∘ =180 ∘ ⇒10x+100 ∘ =180 ∘ ⇒10x=80 ∘ ⇒x=8 ∘ ∴∠A=(2x+40) ∘ =(2×8+40) ∘ =56 ∘ ∠B=∠C=(4x+30) ∘ =(4×8+30) ∘ =62 ∘ ∠A=56 ∘ ∠B=62 ∘ ∠C=62 ∘


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