1.

In an L-C-R circuit, L = 8H, C = 0.5muF, R = 100Omega connected in series. The resonance frequency of the circuit will be…....

Answer»

600 Hz
60 Hz
`250/pi` Hz
5000 Hz

Solution :L=8.0 H, `C=0.5xx10^(-6)F, R=100 Omega`
Resonance FREQUENCY `f_0=1/(2pisqrt(LC))`
`=1/(2pisqrt(8xx0.5xx10^(-6)))`
`=1/(2pixx2xx10^(-3))`
`=1000/(4pi)`
`THEREFORE f_0=250/pi` Hz


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