In an `L-C-R` ereis circuit `R=150Omega, L=0.0750 H` and `C=0.0180muF` . The source has voltage amplitude `V=150V` and a frequencey equal to the resonacne frequency of the circuit. (a) What is the power factor ? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with `C=0.0360muF` and the source frequency is adjusted to the new resonance value. Then, what is the average power delivered by the source?

In an `L-C-R` ereis circuit `R=150Omega, L=0.0750 H` and `C=0.0180muF`

1.	In an `L-C-R` ereis circuit `R=150Omega, L=0.0750 H` and `C=0.0180muF` . The source has voltage amplitude `V=150V` and a frequencey equal to the resonacne frequency of the circuit. (a) What is the power factor ? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with `C=0.0360muF` and the source frequency is adjusted to the new resonance value. Then, what is the average power delivered by the source?
Answer» (a) At resonance frequency, `X_L=X_C,Z=R` and power factor `cosphi=R/Z=1.0` (b) `P=V_(rms)^2/R=((150//sqrt(2))^(2))/(150)=75W` (c) Again `P=V_("rms")^2/R=75W`.

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