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In an `L-C-R` series circuit, `R = sqrt(5) Omega, = 9 Omega, X_(C ) = 7 Omega`. If applied voltage in the circuit is `50 V` then impedance of the circuit in ohm will beA. 2B. 3C. `2 sqrt(5)`D. `3 sqrt(5)` |
Answer» Correct Answer - 2 Impedance, `Z = R + X_(c ) + X_(L)` `= (5 sqrt(5 i) = 7 j + 9 j) = sqrt(5 i) + 2 j` `|Z| = sqrt(5 + 4) = sqrt(9) = 3` |
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