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In an `LR` circuit as shows in Fig.when the swtich is closed, how much time will it take for the current to grow to a value `n` times the maximum value of current (where `n lt 1)`? |
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Answer» We know that `I = (epsilon)/(R ) (1 - e^(-t//tau))` `I = n(epsilon)/(R )` (given) `n = (epsilon)/(R ) = (epsilon)/(R ) (1 - e^(-t//tau))` or `e^(-t//tau) = 1 -n` or `t = tau` In `((1)/(1 - n))` |
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